the dual state of a quantum state $|\psi\rangle$ is denoted as $\langle\psi|$, $$ \langle\psi| = |\psi\rangle^\dagger $$
The inner product between a ket and a bra is defined as:
$$ \begin{aligned} \langle\psi|\phi\rangle &= \underbrace{\sum \alpha_i^* \beta_i}_{{\color{blue}\text{discrete case}}} \quad \text{or} \quad \underbrace{\int \psi^*(x) \phi(x) dx}_{{\color{forestgreen}\text{continuous case}}} \end{aligned} $$ for any quantum state $|\psi\rangle$ $$\|\psi\|^2=\langle\psi|\psi\rangle=1$$Hermitian operators $H = H^{†}$ represent observable quantities. They generate unitary evolutions via:
$$ U = e^{-iHt} $$An observable A can be decomposed as:
$$ H = \sum_k \lambda_k |\psi_k\rangle\langle\psi_k| $$where λₖ are eigenvalues and |ψₖ⟩ are the corresponding eigenstates.
A linear operator U is unitary if:
$$ U^\dagger U = I $$where U† is its conjugate transpose and I is the identity operator.
Quantum states at time $t$ can be written as
$$ |\psi(t)\rangle=\int \psi(x, t)|x\rangle d x $$The wave function $\psi(x,t)$ satisfies the Schrödinger equation:
$$ i\hbar \frac{\partial}{\partial t}\psi(x,t) = -\frac{\hbar^2}{2m}\frac{\partial^2}{\partial x^2}\psi(x,t) + V(x)\psi(x,t) $$For a free particle $(V(x)=0)$, the solution takes the form:
$$ \psi(x,t) = Ae^{i(kx-\omega t)} $$In 3-d space, a particle can be classified into two categories:
In 2-d space, particles can exhibit a continuous range of statistical behavior, these are called anyons.
Common single-qubit gates include:
Hadamard gate:
$$ H = \frac{1}{\sqrt{2}}\begin{pmatrix} 1 & 1 \\ 1 & -1 \end{pmatrix} $$Phase gate:
$$ S = \begin{pmatrix} 1 & 0 \\ 0 & i \end{pmatrix} $$NOT gate (Pauli-X):
$$ X = \begin{pmatrix} 0 & 1 \\ 1 & 0 \end{pmatrix} $$The CNOT gate:
$$ CNOT = |0\rangle\langle0| \otimes I + |1\rangle\langle1| \otimes X $$The maximally entangled Bell state:
$$ |\Phi^+\rangle = \frac{1}{\sqrt{2}}(|00\rangle + |11\rangle) $$Any bipartite pure state can be written as:
$$ |\psi\rangle = \sum_i \sqrt{\lambda_i} |u_i\rangle \otimes |v_i\rangle $$Quantified as:
$$ S = -\sum_i \lambda_i^2 \log(\lambda_i^2) $$The QFT acts on basis states as:
$$ QFT|j\rangle = \frac{1}{\sqrt{N}} \sum_k e^{2\pi ijk/N} |k\rangle $$The Grover operator is:
$$ \mathcal{Q} = (2|s\rangle\langle s| - I) \Omega $$where |s⟩ is the marked state and Ω is the oracle.
Used in Shor's algorithm and other quantum algorithms to extract eigenvalues of unitary operators.